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[Q] Need help with a program.

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By SurajKamble, Junior Member on 31st August 2014, 03:23 PM
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public void click(View view) {
String one = "one";
EditText et = (EditText)findViewById(R.id.editText1);
String entered_text = et.getText().toString();

if(et.getText().toString() == one){
TextView tv1 = (TextView)findViewById(R.id.textView1);
tv1.setText("Correct!");
}
else{
TextView tv = (TextView)findViewById(R.id.textView1);
tv.setText(one+entered_text); }
}
This is a code snippet extracted from my program, i didn't post the whole program because it wasn't necessary, as the program runs fine without any runtime exceptions.
So, the program when executed on eclipse doesn't show any errors and runs fine, but when run the "if" condition "et.getText().toString() == "one"" always returns false even when the "entered_text" is "one" i.e.; it never prints "correct!" and the code always prints "one+entered_text" that is the statement in the else clause. And the interesting thing is, if you enter "one" the output will be "oneone", that is the else statement.
Please help me where i went wrong.
Thanks in advance.
 
 
31st August 2014, 03:48 PM |#2  
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You're passing view argument in function so try initialize edit text with (EditText)view.findViewById(R.id.edittext);
31st August 2014, 03:57 PM |#3  
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Quote:
Originally Posted by panwrona

You're passing view argument in function so try initialize edit text with (EditText)view.findViewById(R.id.edittext);

Thanks for the reply.
I did what you said and got a runtime exception.
31st August 2014, 04:01 PM |#4  
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You're running it in fragment or activity?
31st August 2014, 04:02 PM |#5  
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Quote:
Originally Posted by panwrona

You're running it in fragment or activity?

Activity.
31st August 2014, 05:08 PM |#6  
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Are you initializing it in oncreate or somewhere else?
31st August 2014, 05:25 PM |#7  
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That's easy. Instead of == use text.equals(one)
String are not compared by mathematical signs

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