cat /proc/partitions:
Sum of the blocks in mmcblk0 is 4320039, which is just a bit over 4GiB+128MiB. Need to do more analysis of init file to plumb how this works...
Edit 1: Need to find out what mmcblk0p26 partition is used for and why it needs 1.3GiB. It is most definitely not needed for /system or /cache. Would help if someone can run df command and post the results here. (df > /sdcard/df.txt for convenience)
Edit 2: Thanks dcman008. Looks like mystery is solved. Wasn't really all that mysterious either. Only question is why so much of the flash was allocated to /data.
Code:
major minor #blocks name
[B] 179 0 2,203,648 mmcblk0 [/B] //internal storage
179 1 500 mmcblk0p1
179 2 64 mmcblk0p2
179 3 4,500 mmcblk0p3
179 4 1 mmcblk0p4
179 5 30,000 mmcblk0p5
179 6 12,500 mmcblk0p6
179 7 2,048 mmcblk0p7
179 8 3,072 mmcblk0p8
179 9 2,048 mmcblk0p9
179 10 1,024 mmcblk0p10
179 11 1,024 mmcblk0p11
179 12 8,751 mmcblk0p12
179 13 3,072 mmcblk0p13
179 14 3,072 mmcblk0p14
179 15 1,024 mmcblk0p15
179 16 8,957 mmcblk0p16
179 17 256 mmcblk0p17
179 18 1,024 mmcblk0p18
179 19 1,024 mmcblk0p19
179 20 1,280 mmcblk0p20
179 21 8,701 mmcblk0p21
179 22 4,096 mmcblk0p22
179 23 256 mmcblk0p23
179 24 256 mmcblk0p24
[B] 179 25 425,726 mmcblk0p25[/B] //system partition
[B] 179 26 1,361,920 mmcblk0p26[/B] //data partition
[B] 179 27 209,715 mmcblk0p27[/B] //cache
179 28 20,480 mmcblk0p28
Edit 1: Need to find out what mmcblk0p26 partition is used for and why it needs 1.3GiB. It is most definitely not needed for /system or /cache. Would help if someone can run df command and post the results here. (df > /sdcard/df.txt for convenience)
Edit 2: Thanks dcman008. Looks like mystery is solved. Wasn't really all that mysterious either. Only question is why so much of the flash was allocated to /data.
Last edited: