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[Q] Change start-point of analog clock & calculate [ar]

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By bvt-1, Senior Member on 9th May 2014, 03:22 AM
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Hello,

I want to create a analog clock, but 12 o`clock shouldn`t begin on the top, it should start with 12 o`clock at the point of 2 o`clock
(sorry, my english is awful)

So, the starting point should be at 20 degrees, because the background is distorted.

Now I have

[r] $(360/60*#dm#)$ [/r]
$#dm#>360?((360/60*#dm#+20)-360)360/60*#dm#+20)$

What is wrong? Doesn`t work

And is there a possibility to calculate the value of [ar] ---> my rectangle (clock hand) is 34 high ...

Thx an d Greets
 
 
9th May 2014, 05:51 PM |#2  
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9th May 2014, 07:27 PM |#3  
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Quote:
Originally Posted by bvt-1

Hello,

I want to create a analog clock, but 12 o`clock shouldn`t begin on the top, it should start with 12 o`clock at the point of 2 o`clock
(sorry, my english is awful)

So, the starting point should be at 20 degrees, because the background is distorted.

Now I have

[r] $(360/60*#dm#)$ [/r]
$#dm#>360?((360/60*#dm#+20)-360)360/60*#dm#+20)$

What is wrong? Doesn`t work

And is there a possibility to calculate the value of [ar] ---> my rectangle (clock hand) is 34 high ...

Thx an d Greets

But.......2 o'clock is 60 degrees.....

Try this

[r] $(60+(360/60*#dm#))$ [/r]

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9th May 2014, 07:47 PM |#4  
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Great, works :thumbup::thumbup:
Many many thanks :thumbup:

And did you know,,how to calculate [ar] ?

... oOo ...
9th May 2014, 08:16 PM |#5  
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Quote:
Originally Posted by bvt-1

Great, works :thumbup::thumbup:
Many many thanks :thumbup:

And did you know,,how to calculate [ar] ?

... oOo ...

Mmm...... [ar] work with [as], for [as] you can use the same formula, and for [ar] use simply, for example, 5, 10, 15 or -5, -10, -15 or other valute ( without $ ), try different.

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Last edited by expinox; 9th May 2014 at 08:42 PM.
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