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ArrayList<Integer> 's remove method confusing?

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By arpitkh96, Senior Member on 22nd June 2014, 03:53 PM
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Suppose I added a digit '1' to the arraylist<Integer> which is at position 0.So when I call remove method like this.
array.remove(1);
It gives an exception.although the method remove(object) exists.so I how can I remove the object(integer) by not using the position

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22nd June 2014, 05:16 PM |#2  
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Quote:
Originally Posted by arpitkh96

Suppose I added a digit '1' to the arraylist<Integer> which is at position 0.So when I call remove method like this.
array.remove(1);
It gives an exception.although the method remove(object) exists.so I how can I remove the object(integer) by not using the position

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array.remove(new Integer(1));
22nd June 2014, 07:08 PM |#3  
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Quote:
Originally Posted by SimplicityApks

array.remove(new Integer(1));

That didn't worked.I am using it like this
Code:
 
//CopyIds is the arraylist
private BroadcastReceiver Copy_Receiver = new BroadcastReceiver(){

@Override
public void onReceive(Context arg0, Intent arg1) {
// TODO Auto-generated method stub
Bundle b=arg1.getExtras();
if(b!=null){
int id=b.getInt("id");
Integer id1=new Integer(id);
if(CopyIds.contains(id)){

boolean completed=b.getBoolean("COPY_COMPLETED",false);
View process=rootView.findViewWithTag("copy"+id);
  if(completed){ rootView.removeViewInLayout(process);CopyIds.remove(id1);}
else{
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
long total=b.getLong("total");
long done=b.getLong("done");
  ((TextView)process.findViewById(R.id.progressText)).setText("Copying \n"+name+"\n"+utils.readableFileSize(done)+"/"+utils.readableFileSize(total)+"\n"+p1+"%");
ProgressBar p=(ProgressBar)process.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);}
}else{
View root=getActivity().getLayoutInflater().inflate(R.layout.processrow, null);
root.setPaddingRelative(10,10,10,10);
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
root.setTag("copy"+id);
((TextView)root.findViewById(R.id.progressText)).setText("Copying \n"+name);
ProgressBar p=(ProgressBar)root.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);
CopyIds.add(id);
rootView.addView(root);
}
}
}};
Log says error receiving broadcast.arryindexoutofbounds exception ,size 1 index 1

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22nd June 2014, 09:19 PM |#4  
SimplicityApks's Avatar
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Quote:
Originally Posted by arpitkh96

That didn't worked.I am using it like this

Code:
 
//CopyIds is the arraylist
private BroadcastReceiver Copy_Receiver = new BroadcastReceiver(){

@Override
public void onReceive(Context arg0, Intent arg1) {
// TODO Auto-generated method stub
Bundle b=arg1.getExtras();
if(b!=null){
int id=b.getInt("id");
Integer id1=new Integer(id);
if(CopyIds.contains(id)){

boolean completed=b.getBoolean("COPY_COMPLETED",false);
View process=rootView.findViewWithTag("copy"+id);
  if(completed){ rootView.removeViewInLayout(process);CopyIds.remove(id1);}
else{
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
long total=b.getLong("total");
long done=b.getLong("done");
  ((TextView)process.findViewById(R.id.progressText)).setText("Copying \n"+name+"\n"+utils.readableFileSize(done)+"/"+utils.readableFileSize(total)+"\n"+p1+"%");
ProgressBar p=(ProgressBar)process.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);}
}else{
View root=getActivity().getLayoutInflater().inflate(R.layout.processrow, null);
root.setPaddingRelative(10,10,10,10);
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
root.setTag("copy"+id);
((TextView)root.findViewById(R.id.progressText)).setText("Copying \n"+name);
ProgressBar p=(ProgressBar)root.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);
CopyIds.add(id);
rootView.addView(root);
}
}
}};
Log says error receiving broadcast.arryindexoutofbounds exception ,size 1 index 1

Strange since I don't get any compile time errors (sorry don't have time to test it right now) and that should be the way to do it...

Anyway, if it still doesn't work for you, just manually search for the right index using get().equals in a for loop and remove the element at the right index then... (that's what the remove(Object) method does anyway).
23rd June 2014, 02:56 AM |#5  
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Quote:
Originally Posted by SimplicityApks

array.remove(new Integer(1));

That works. But why ArrayList is not generified. I would like to use it like:
Code:
arrayList.<Integer>remove(new Integer(1));
It would throw Compiler time Error in case if you pass object of wrong type, which would safe time people like OP.
23rd June 2014, 08:16 AM |#6  
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Quote:
Originally Posted by SimplicityApks

Strange since I don't get any compile time errors (sorry don't have time to test it right now) and that should be the way to do it...

Anyway, if it still doesn't work for you, just manually search for the right index using get().equals in a for loop and remove the element at the right index then... (that's what the remove(Object) method does anyway).

I solved it

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