ArrayList<Integer> 's remove method confusing?

arpitkh96 said:

Suppose I added a digit '1' to the arraylist<Integer> which is at position 0.So when I call remove method like this.
array.remove(1);
It gives an exception.although the method remove(object) exists.so I how can I remove the object(integer) by not using the position

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arpitkh96 said:

That didn't worked.I am using it like this

Code:

//CopyIds is the arraylist
private BroadcastReceiver Copy_Receiver = new BroadcastReceiver(){

@Override
public void onReceive(Context arg0, Intent arg1) {
// TODO Auto-generated method stub
Bundle b=arg1.getExtras();
if(b!=null){
int id=b.getInt("id");
Integer id1=new Integer(id);
if(CopyIds.contains(id)){

boolean completed=b.getBoolean("COPY_COMPLETED",false);
View process=rootView.findViewWithTag("copy"+id);
  if(completed){ rootView.removeViewInLayout(process);CopyIds.remove(id1);}
else{
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
long total=b.getLong("total");
long done=b.getLong("done");
  ((TextView)process.findViewById(R.id.progressText)).setText("Copying \n"+name+"\n"+utils.readableFileSize(done)+"/"+utils.readableFileSize(total)+"\n"+p1+"%");
ProgressBar p=(ProgressBar)process.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);}
}else{
View root=getActivity().getLayoutInflater().inflate(R.layout.processrow, null);
root.setPaddingRelative(10,10,10,10);
String name=b.getString("name");
int p1=b.getInt("p1");
int p2=b.getInt("p2");
root.setTag("copy"+id);
((TextView)root.findViewById(R.id.progressText)).setText("Copying \n"+name);
ProgressBar p=(ProgressBar)root.findViewById(R.id.progressBar1);
p.setProgress(p1);
p.setSecondaryProgress(p2);
CopyIds.add(id);
rootView.addView(root);
}
}
}};

Log says error receiving broadcast.arryindexoutofbounds exception ,size 1 index 1

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SimplicityApks said:

array.remove(new Integer(1));

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arrayList.<Integer>remove(new Integer(1));