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# need some math help pls(urgent)

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 djteotancolis 19th May 2010, 01:56 AM Senior Member - OP Thanks Meter 18 Posts: 1,125 Join Date: Feb 2010 Location: Thane More Info >  DONATE TO ME need some math help pls(urgent) hey everyone i would be greatful to your'll if you could help me in math-geometry...this is slopes and lines 1:line through (-8,-2) and parallel to the line x = 5 2:Line through (-1,3) and parallel to the line 3x + 5y = 15 3:line through (8,0) and perpendicular to the line 3x + 4y = 12 pls give me the solution and the way of solving it thanx REPLY
 ddotpatel 19th May 2010, 02:35 AM Senior Member Thanks Meter 7 Posts: 1,161 Join Date: Mar 2010 Location: Leeds, UK More Info > 1st one is easy,... Let me remember the rest. . . Favourite Useful Links,... BTDAG's [Guide] Complete Newbie Guide to Install a Custom Rom & Newbie FaQ PHAELOX's [HOW TO] Make your own bootscreen and create signed zip Some useful info from BONESY on adding apps to a base ROM here --> How to create "update.zip" for integrate apps? Past to present,... Nokia 3330, 6120, 6820, 6600, 6630, N80, N73, 5800 Never again,... Now,... HTC HERO BABY!!! REPLY

ddotpatel
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Quote:
 Originally Posted by djteotancolis thanx for your help in math but i need to give a answer in number so what should i write?
OK,... So the line they gave you was x=5. This is because x IS ALWAYS 5.
So on the line that I've put, the value for y is changing,... but ,... x IS ALWAYS ????

So,......
.
.
BTDAG's [Guide] Complete Newbie Guide to Install a Custom Rom & Newbie FaQ
PHAELOX's [HOW TO] Make your own bootscreen and create signed zip
Some useful info from BONESY on adding apps to a base ROM here --> How to create "update.zip" for integrate apps?

Past to present,... Nokia 3330, 6120, 6820, 6600, 6630, N80, N73, 5800
Never again,... Now,... HTC HERO BABY!!!

djteotancolis
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Quote:
 Originally Posted by ddotpatel OK,... So the line they gave you was x=5. This is because x IS ALWAYS 5. So on the line that I've put, the value for y is changing,... but ,... x IS ALWAYS ???? So,......
thats what given in the textbook
 djteotancolis 19th May 2010, 02:51 AM Senior Member - OP Thanks Meter 18 Posts: 1,125 Join Date: Feb 2010 Location: Thane More Info >  DONATE TO ME we need to find the solution and not the graph REPLY
 Legend112 19th May 2010, 03:00 AM Member Thanks Meter 0 Posts: 32 Join Date: Apr 2010 More Info > Re: need some math help pls(urgent) Edit: Y = a(x-x0)+y0 as far as I remember ------------------------------------- Sent via the XDA Tapatalk App REPLY
 ddotpatel 19th May 2010, 03:00 AM Senior Member Thanks Meter 7 Posts: 1,161 Join Date: Mar 2010 Location: Leeds, UK More Info > Im LEADING you to the answer!!!!!! Answer what I just asked you!!!!! x IS ALWAYS ??????? x= ......... . . . . . . . x = -8 . . Favourite Useful Links,... BTDAG's [Guide] Complete Newbie Guide to Install a Custom Rom & Newbie FaQ PHAELOX's [HOW TO] Make your own bootscreen and create signed zip Some useful info from BONESY on adding apps to a base ROM here --> How to create "update.zip" for integrate apps? Past to present,... Nokia 3330, 6120, 6820, 6600, 6630, N80, N73, 5800 Never again,... Now,... HTC HERO BABY!!! REPLY

djteotancolis
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Quote:
 Originally Posted by ddotpatel Im LEADING you to the answer!!!!!! Answer what I just asked you!!!!! x IS ALWAYS ??????? x= ......... . . . . . . . x = -8
oh ok thanx thats for the first one right?
sorry m just a bit tensed that i cant pay proper attention
 ddotpatel 19th May 2010, 03:01 AM Senior Member Thanks Meter 7 Posts: 1,161 Join Date: Mar 2010 Location: Leeds, UK More Info > 2:Line through (-1,3) and parallel to the line 3x + 5y = 15 When x=0 3(0) + 5y = 15 5y=15 Y=3 So when x=0,.. y=3 ,...(0,3) When y=0 3x + 5(0) = 15 3x=15 X=5 So when y=0,.. x=5,.. (5,0) Plot both on graph, then join the two. . . Favourite Useful Links,... BTDAG's [Guide] Complete Newbie Guide to Install a Custom Rom & Newbie FaQ PHAELOX's [HOW TO] Make your own bootscreen and create signed zip Some useful info from BONESY on adding apps to a base ROM here --> How to create "update.zip" for integrate apps? Past to present,... Nokia 3330, 6120, 6820, 6600, 6630, N80, N73, 5800 Never again,... Now,... HTC HERO BABY!!! REPLY

djteotancolis
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Quote:
 Originally Posted by ddotpatel 2:Line through (-1,3) and parallel to the line 3x + 5y = 15 When x=0 3(0) + 5y = 15 5y=15 Y=3 So when x=0,.. y=3 ,...(0,3) When y=0 3x + 5(0) = 15 3x=15 X=5 So when y=0,.. x=5,.. (5,0) Plot both on graph, then join the two.
ok but what solution should i write to the question? we arnt doin drawing of graphs just the writing works

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