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{ask} cm what price??

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By koplax antiek, Member on 2nd February 2014, 10:22 AM
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hello developers xperia l
I want to ask if to create a 10.1 cm or 10.2 should pay how ??
maybe we can talk about that xperia l cm her release

thank you
 
 
2nd February 2014, 10:29 AM |#2  
Sena Ferdy's Avatar
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Quote:
Originally Posted by koplax antiek

hello developers xperia l
I want to ask if to create a 10.1 cm or 10.2 should pay how ??
maybe we can talk about that xperia l cm her release

thank you

Up up
2nd February 2014, 10:57 AM |#3  
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Don't be silly.

A quote from a CM thread:

Quote:

CyanogenMod is a free, community built, aftermarket firmware distribution of Android, which is designed to increase performance and reliability over stock Android for your device.

You don't have to purchase Cyanogenmod or pay any developer to build it. I'm sure it's against XDA rules anyway.
2nd February 2014, 11:06 AM |#4  
koplax antiek's Avatar
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thanxs dude ...
ok ok
sorry
2nd February 2014, 08:06 PM |#5  
Aerkhanite's Avatar
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Quote:
Originally Posted by Desmaize38

Don't be silly.

A quote from a CM thread:



You don't have to purchase Cyanogenmod or pay any developer to build it. I'm sure it's against XDA rules anyway.

You realize that the "Free" does not imply you don't have to pay, but that it respects your freedom?
They could start selling it right now if they'd want to, and still refer to it as free.
3rd February 2014, 09:50 AM |#6  
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Bounty threads aren't really allowed on xda. Reporting now.
3rd February 2014, 01:02 PM |#7  
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Quote:
Originally Posted by Desmaize38

Don't be silly.

A quote from a CM thread:



You don't have to purchase Cyanogenmod or pay any developer to build it. I'm sure it's against XDA rules anyway.

Hit the nail on the head here. Developers should create a ROM for fun (hobby) and not go get paid for it. Besides CM is free/ Open Source so paying someone to build it for you just wouldn't be rite and i'm sure CM wouldn't be happy wth a developer on XDA putting a price on their work which they do for free.

Closing this thread,

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