3.7v doesn't seem to work, even though the battery I'm trying to emulate has only 2 wires.
I have a Moto E 2nd gen model # 1526. The battery is 'non-replaceable' and there are only two wires emerging from the battery that connect to the phone. I can't post links, but if you google XT1526 battery you should see what the thing looks like. Anyway, because there are only two wires connected to the phone, I was under the assumption that simply applying ~3.8v across those two wires (with sufficient amperage) would allow the phone to work. Short answer, it doesn't, and I don't know why or what to do. Long answer:
I purchased a meanwell 150W PSU capable of supplying ~3.2 to 4.2V and controlled by potentiometer. Using this PSU, a breadboard, voltmeter and connectors, I tried operating the phone by supplying ~3.7 through ~4.2V directly into the battery connector, with no luck. I did notice a short voltage drop when trying to power on the phone. The screen would light up briefly (nothing displayed) and then shut off.
Next step, I disassembled the top of the battery and found a small, thin PCB. This board is wired directly to the battery outputs, and has a couple of surface mount things soldered onto it, and also has the two tiny output wires and battery connector that connects to the phone. I then tried wiring the Meanwell PSU to this board where the battery outputs connect, and then connected the battery connector to the phone, and applied the same range of voltage. Still no dice.
So it doesn't appear to be as simple as voltage/current, but I'm not sure what else to try. I have a test PSU from a computer than can supply 5v, 7v, 12v, but those don't seem likely to work, because that would mean that the tiny PCB in the battery is a voltage rectifier, and if that were the case, it seems to me that it would overheat.
Any ideas/suggestions?