- Sep 7, 2015
Mine so far has gone from 10 percent to 49 in 2 and a half hours
Thanks for this. A Logitech cable used to charge their products (mice, keyboards) outputs 1900, for those interested.
Not only is it very detailed (voltage, current, power, temperature) it also has very detailed graphs as well...It was really fast.. I don't have a number for a full charge. But right now, it went from 18 to 25 in a couple of minutes.
I'll try and get around to testing it with Battery Monitor Widget.
Not only is it very detailed (voltage, current, power, temperature) it also has very detailed graphs as well...
that's interesting, I'm using my original cable for 2,5 years only, so I'd assume that how you care about your s#!t is what you getChange the cable. The problem is known. Buy a cable with 2.1A output. Original cable of Samsung is pure **** because fails after some months.
Same here, genuine Samsung charger and diet after 4 months!!! Using my old htc charger (came with the htc diamond), but it's only 1A so take a bit to charge (upto 3 hours).Always used it with care. I'd got 2 Note 2 and two times cables was failed. Also with a galaxy s4. I bougth an original travel charger Samsung with 2A and after some months is died with slow charge.
For me, 2000 and 1900 gets my phone very hot, sometimes crashy. I have a rubber cover around the phone, so heat problems are worse for me, and recently it was very warm. 1800 and 1700 cause no obvious issues for me on Marshmallow. I assume they are pretty safe. In general, more current will maybe make the battery not last as long, but not actually damage it. I am comfortable recommending charging speeds below 1900 to anyone.it is safe to charge my phone with 1800 ma rate? note 2 original charger generate a lot of heat , 1800ma can damage the battery? thanks
hi, it is safe to charge my phone with 1800 ma rate? note 2 original charger generate a lot of heat , 1800ma can damage the battery? thanks
Yes it is - the onboard chip limits the current that the battery can safely take. If it results in the phone getting hot your problem is definitely the battery. As Li-Ion batteries age their internal resistance increase, resulting in greater heat generation. Excessive heat is a surefire sign you need a new battery.
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Phone temperature is ok and the battery temp 39-40 c max when charging, original charger is hot when i use it with 1800 ma.
The Maxim 77693 charger chip is capable of detecting voltage differentials in the charger lines; if it decides that this differential is too great, then it reports a sort of "unstable power" to the kernel, which in turn reduces the input current in 100mA steps until the chip stops reporting problems. That's what's happening.What physics is behind this huge difference in cables' performance? Is it size/internal resistance or are there other factors?
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Probably nothing much, especially considering resistive cable losses.First thing, I would be carefull with that charger as it supplies 5.3V and not the default 5V. I do not know what will be the effect on your phone/battery if you continue using that.
Although I'd play it safe with my motherboard (I have a 4 year old machine - I suppose newer machines have higher output USB ports), as for the charger I've been using these values or slight variants thereof ever since I loaded this kernel several months ago and made some experimentation with it. In the course of this experimentation my chargers did not suffer, I've been able to steady my charging rate and, probably most importantly for those who do not care for the electrical concepts, the battery never overheated.But to your question - I do not know if those values indicate "input current" or "battery charging current" so I would strongly recommend using STweaks or TricksterMod as they have clearly labelled settings.
To values then:
DCP and AC Charger Input Current - set 2000
DCP and AC Charger Charge Current - set 1400
CDP and SDP Input current - set 1000
CDP and SDP Charging current - set 1000
Those are safe values, unless you have some very bad charger withous overheat protections or really, really bad USB port in your PC you will be safe with those values.
The INPUT CURRENT is the total current going into the phone from the charger. It defines the maximum current to ask from the charger. Going above what the charger can actually produce (let's say, asking 2.1A from a 2.0A charger) could lead to charger overheating, which may cause temporary thermal shutdown or could even burn the chip itself and by that I don't mean the chip will catch on fire, you probably won't see nor smell anything funny except that suddenly there is no output anymore no matter how long you wait.Oh ok I think I get what he was saying now. The input current is in regards to what's provided while using the phone, and the battery charge current is in regards to charging the battery only. I don't have those options with my kernel so I had no clue what he was talking about, but now it makes sense.
It's unlikely you will, especially considering losses from the cable, you probably get less then 5V at the device. Good rule of thumb: check to see if it gets hot at the microUSB port (not merely warm).As far as the 5.3V charger goes I've actually been using it for about 6 months with this phone and I haven't had any issues whatsoever
Don't worry about the charger, if it's UL tested, it won't burn the place down. They really, I mean, really torture these things to make sure it won't cause serious damage even under the most extreme conditions. The only thing that is remotely dangerous on a cell phone is the battery, and it has a chip that will blow a fuse before it goes into meltdown. If you use an OEM battery there should be no problem.I'd also rather not burn my house down while I'm sleeping
I doubt the OEM battery will let you charge it any faster (remember the battery chip is the ultimate boss here), so I don't see the point, unless that current is meant to apply for the total of Charging and Input.Anyway as far as the AC Charger Current goes with my kernel if it helps the default untouched setting is at 1700mA, and I have been using this charger with that setting and I haven't had any problems so far. So I was just wondering if I could turn it up a little to possibly decrease the amount of time it takes to fully charge the phone, but now I'm under the impression that it doesn't work like that? If that AC Charger Current that I can adjust with my kernel does control only the battery charge current and set to 1700mA by default, what would the advantages of increasing that be if it's not possible to increase the rate of charge?
The current is controlled this way: Charger Output -> Kernel Power Management -> Battery Charge ControllerI guess that's where I'm confused because if you increase the amount of charge coming from the charger (and as long as the charger is capable and can handle it), wouldn't that technically make the battery charge faster? I'm definitely not disagreeing with what anyone has said whatsoever just to clarify, I'm just asking because I think I'm missing something.
Do yourself a favour and use Battery Monitor Widget instead, and check current over time, at least 20 minutes. GCC is pretty useless.Ok thank you for responding and now that I understand that there's difference between input and battery charge current, I'm not anywhere near as confused as I was before lol. I understand what you're saying about the battery having a max charge restriction, so I'm assuming that the GCC app is only showing the input and not what's going to the battery (battery charge current) correct? The reason I'm saying that us because whenever I change the value of the AC Charger Current, it reflects the same in the GCC app so for example if I set it to 1900mA, it shows all 3 max current and average at 1900mA. So if the battery has a limit of max charge current, GCC would only show up to that limit if it were displaying the battery charge current correct? Anyway I appreciate you pointing out that it's a 5.3V charger because it never even crossed my mind to be honest, and I definitely understand that just because it's working fine now doesn't mean that something couldn't happen eventually. I'll start looking for another charger to use just to be on the safe side because I can see it toasting my phone out of nowhere with my luck! Lol Thanks again!
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When the phone is used, and it is consuming ~600mA... Say it has 2000mA current input and 1400mA current charge... It will charge battery by 1400mA BUT the phone will USE 600mA provided from the charger (to not use the battery)? Like a laptop when it is plugged in to the charger but with the battery not inserted?[/quite]
Right. However should the power consumption rise, it will get the power where it comes from and the battery WILL CHARGE SLOWER, or even discharge.
Right.Using a higher voltage charger could alleviate amy potential loss through the cable. Right?
Congratulations, you just graduated from Electricity 001 and probably now understood why we need high voltage to carry electricity over long distances~0.2V is anyway gonna be wasted... And the phone's got an internal regulator which only takes in 4.35V (so the rest translates to a bit higher current, right?), so I'd say you're safe...
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---------- Post added at 07:41 PM ---------- Previous post was at 07:31 PM ----------
Although some of it is indeed lost as heat, the device only uses what it needs. That's the basic idea behind modern switching power supplies.That's awesome I was just going to mention that the internal regulator limits the voltage to 4.35v (just like you said), so I wouldn't think it would matter anyway.
Imagine you have more power than you need. Instead of putting a resistor in between and losing the excess as heat, you simply take the full amount, but only for a certain amount of time, let's say, 80% of it, to get an effective 4V from 5V, so the power is effectively SWICHED on and off, usually several thousand times a second, this averages out to what you need..But I was also going to say that I have no idea what happens to the rest of the voltage though, so I appreciate you clearing that up!
---------- Post added at 07:43 PM ---------- Previous post was at 07:41 PM ----------
Two thumbs up, Man!As far as I know, when you lower the voltage, the current goes up. As far as I know = I could be entirely wrong.
The voltage regulator does transform the input voltage (5V, 5.3V...) to a steady 4.35V, but I don't know how much voltage it can take until it breaks... I'd say 5.3V is not enough to cause any damage, and it can be handled by the internal regulator easily.
I mean... what the f***, this phone has a chip to detect unstable current & broken cables and it doesn't have a powerful enough voltage regulator to work with +/-0.5V?
As far as the other thing goes... input/charge current (1A goes in the battery, 0.5A goes in the phone, laptop style)... I really don't know and am waiting for others to answer on the issue.